What is the domain of f(x)=sqrt(x+3)+sqrt(9-x) ?

The domain of f(x)=sqrt(x+3)+sqrt(9-x) is -3<= x<= 9

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domain of f(x)=sqrt(x+3)+sqrt(9-x)

domain

f (x) = x + 3 + 9 - x

- 3 \leq x \leq 9

Interval Notation

[- 3, 9]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 9

The function domain

- 3 \leq x \leq 9

f (x) = ln (x - 1) + ln (5 - x)

f (x) = \frac{x ^{2} - x - 2}{x ^{2} - 7 x + 10}

2 + x - x^{2}

f (x) = x (x - 4)

f (x) = arccos (\frac{1}{2 - x})

What is the domain of f(x)=sqrt(x+3)+sqrt(9-x) ?
The domain of f(x)=sqrt(x+3)+sqrt(9-x) is -3<= x<= 9