What is the domain of g(x)= 1/(sqrt(x-2)) ?

The domain of g(x)= 1/(sqrt(x-2)) is x>2

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domain of g(x)= 1/(sqrt(x-2))

domain

g (x) = \frac{1}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (x) = x^{2} + 3 x - 1

y = 2 x + 1

- x^{2} - 2

f (x) = lo g_{x} (25 - x^{2})

lo g_{3} ((y + 1)^{2}) = 2

What is the domain of g(x)= 1/(sqrt(x-2)) ?
The domain of g(x)= 1/(sqrt(x-2)) is x>2