What is the domain of f(x)=(19)/(sqrt(3x-12)) ?

The domain of f(x)=(19)/(sqrt(3x-12)) is x>4

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domain of f(x)=(19)/(sqrt(3x-12))

domain

f (x) = \frac{19}{3 x - 12}

x > 4

Interval Notation

(4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

x > 4

f (x) = x^{2} - 16 + 36 - x^{2}

f (x, y) = x^{2} - 5 x - 6

f (x) = 4 + lo g_{10} (x - 1)

1 - x

What is the domain of f(x)=(19)/(sqrt(3x-12)) ?
The domain of f(x)=(19)/(sqrt(3x-12)) is x>4