What is the domain of (2x^2)/(x^2-9) ?

The domain of (2x^2)/(x^2-9) is x 3

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domain of (2x^2)/(x^2-9)

domain

\frac{2 x ^{2}}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = \frac{x ^{2} + 1}{x ^{2} - 4}

f (x) = lo g_{5} (4 - x)

f (x) = - x + \frac{1}{2 + x}

f (x) = \frac{2 x + 3}{x ^{3} - 4 x}

f (x) = \frac{1}{x ^{2} + 2 x - 3}

What is the domain of (2x^2)/(x^2-9) ?
The domain of (2x^2)/(x^2-9) is x<-3\lor-3<x<3\lor x>3