What is the domain of f(x)=ln(x/(x^2+1)) ?

The domain of f(x)=ln(x/(x^2+1)) is x>0

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domain of f(x)=ln(x/(x^2+1))

domain

f (x) = ln (\frac{x}{x ^{2} + 1})

x > 0

Interval Notation

(0, \infty)

Solution steps

Find positive values for logs:

x > 0

The function domain

x > 0

f (x) = ln (4 x - 5)

\frac{x + 2}{x ^{2} - 121}

ln (9 - x^{2})

g (x) = 5 x + 1

lo g_{10} (x^{2} - 3 x) - lo g_{10} (x + 5)

What is the domain of f(x)=ln(x/(x^2+1)) ?
The domain of f(x)=ln(x/(x^2+1)) is x>0