What is the domain of (1-6x+9x^2)/(3x-1) ?

The domain of (1-6x+9x^2)/(3x-1) is x 1/3

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domain of (1-6x+9x^2)/(3x-1)

domain

\frac{1 - 6 x + 9 x ^{2}}{3 x - 1}

x < \frac{1}{3} or x > \frac{1}{3}

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{3}

The function domain

x < \frac{1}{3} or x > \frac{1}{3}

f (x) = lo g_{4} (\frac{2 x + 5}{x ^{2}})

f (x) = \frac{7}{( 2 x - 6 ) ^{2}}

f (x) = ln (x + 2) - \frac{1}{3 - x}

f (x) = ln (x^{2} + 2 x - 8)

f (x) = \frac{x + 6}{2 x - 4}

What is the domain of (1-6x+9x^2)/(3x-1) ?
The domain of (1-6x+9x^2)/(3x-1) is x< 1/3 \lor x> 1/3