What is the perpendicular 2x-3y=6,(-2,-3) ?

The perpendicular 2x-3y=6,(-2,-3) is y=-3/2 x-6

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perpendicular 2x-3y=6,(-2,-3)

perpendicular

2 x - 3 y = 6, (- 2, - 3)

y = - \frac{3}{2} x - 6

Solution steps

Find the line

y = mx + b

perpendicular to

2 x - 3 y = 6

that passes through

(- 2, - 3)

Find the slope of

2 x - 3 y = 6 : m = \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(- 2, - 3) : y = - \frac{3}{2} x - 6

y = - \frac{3}{2} x - 6

f (x) = \frac{x ^{3} - 3 x ^{2} - 4 x}{x - 4}

f (x) = h (x) = \frac{x + 2}{x ^{2} + 5 x + 6}

f (x) = x^{2} - 2 x - 2

f (x) = 3 (x + 4)

6 x - y = 9

What is the perpendicular 2x-3y=6,(-2,-3) ?
The perpendicular 2x-3y=6,(-2,-3) is y=-3/2 x-6