What is the domain of ((2x^2-6x+4))/(-3x-5) ?

The domain of ((2x^2-6x+4))/(-3x-5) is x -5/3

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domain of ((2x^2-6x+4))/(-3x-5)

domain

\frac{( 2 x ^{2} - 6 x + 4 )}{- 3 x - 5}

x < - \frac{5}{3} or x > - \frac{5}{3}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{3}

The function domain

x < - \frac{5}{3} or x > - \frac{5}{3}

f (x) = \frac{x + 9}{- x ^{2} - 3 x + 4}

2^{- x}

f (x) = \frac{5}{4 x + 24}

f (x) = ln (9 x - 21) + 2021

- 3 x + 4

What is the domain of ((2x^2-6x+4))/(-3x-5) ?
The domain of ((2x^2-6x+4))/(-3x-5) is x<-5/3 \lor x>-5/3