What is the domain of f(x)=sqrt((6x)/(x^2-1)) ?

The domain of f(x)=sqrt((6x)/(x^2-1)) is -1 1

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domain of f(x)=sqrt((6x)/(x^2-1))

domain

f (x) = \frac{6 x}{x ^{2} - 1}

- 1 < x \leq 0 or x > 1

Interval Notation

(- 1, 0] \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

- 1 < x \leq 0 or x > 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x \leq 0 or x > 1

cos (2 x + 5), 0 \leq x \leq 2 π

f (x) = \frac{100 - x ^{2}}{x ^{2} + 4 x - 21}

f (x) = \frac{x + 3}{x ^{2} - 16}

f (x) = \frac{x ^{2} + 2 x - 3}{2 x ^{2} - 4 x}

f (x) = \frac{1}{1 - x}

What is the domain of f(x)=sqrt((6x)/(x^2-1)) ?
The domain of f(x)=sqrt((6x)/(x^2-1)) is -1<x<= 0\lor x>1