What is the inverse of f(x)=18500(0.09-x^2) ?

The inverse of f(x)=18500(0.09-x^2) is sqrt(-0.00005…x+0.09),-sqrt(-0.00005…x+0.09)

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inverse of f(x)=18500(0.09-x^2)

inverse

f (x) = 18500 (0.09 - x^{2})

- 0.00005 \dots x + 0.09, - - 0.00005 \dots x + 0.09

Solution steps

y = 18500 (0.09 - x^{2})

Replace

x

with

y

x = 18500 (0.09 - y^{2})

Solve for

y, x = 18500 (0.09 - y^{2})

- 0.00005 \dots x + 0.09, - - 0.00005 \dots x + 0.09

f (x) = x + \frac{1}{x - 2}

(2, - 7), (2, 1)

- 2 x^{2} + 16 x - 31

f (x) = (4 x + 5)^{\frac{1}{5}}

y = \frac{( x ^{2} )}{1 - x}

What is the inverse of f(x)=18500(0.09-x^2) ?
The inverse of f(x)=18500(0.09-x^2) is sqrt(-0.00005…x+0.09),-sqrt(-0.00005…x+0.09)