What is the domain of sqrt(x^2-x) ?

The domain of sqrt(x^2-x) is x = 1

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domain of sqrt(x^2-x)

domain

x^{2} - x

x \leq 0 or x \geq 1

Interval Notation

(- \infty, 0] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 1

The function domain

x \leq 0 or x \geq 1

\frac{ln ( x )}{ln ( x - 1 )}

y = lo g_{x} (36 - x^{2})

6 x

f (x) = \frac{x - 5}{x ^{2} - 64}

arcsin (\frac{x - 8}{9}) + 5

What is the domain of sqrt(x^2-x) ?
The domain of sqrt(x^2-x) is x<= 0\lor x>= 1