What is the domain of g(x)=sqrt(x+1) ?

The domain of g(x)=sqrt(x+1) is x>=-1

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domain of g(x)=sqrt(x+1)

domain

g (x) = x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

\frac{1}{( y ^{2} + 1 ) ^{\frac{1}{2}}} y

4 x + 7

f (x) = lo g_{3} (x + 3)

f (x) = 8 x + 5

f (x) = \frac{3 x + 7}{x ^{2} + 5 x + 4}