What is the domain of y= 1/(sqrt(x^2-1)) ?

The domain of y= 1/(sqrt(x^2-1)) is x 1

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domain of y= 1/(sqrt(x^2-1))

domain

y = \frac{1}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = ∣ x - 4 ∣ + 2

f (x) = \frac{x}{1 - x ^{2}}

f (x) = \frac{2 x - 2}{9 x + 36}

f (x) = 5 + (ln (x^{2} - 9))^{2}

f (x) = x^{2} - 7 x + 12

What is the domain of y= 1/(sqrt(x^2-1)) ?
The domain of y= 1/(sqrt(x^2-1)) is x<-1\lor x>1