What is the domain of f(x)=(x^2-x)/(sqrt(x^2-1)) ?

The domain of f(x)=(x^2-x)/(sqrt(x^2-1)) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^2-x)/(sqrt(x^2-1))

domain

f (x) = \frac{x ^{2} - x}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = 2 arcsin (\frac{x}{2}) + π

\frac{x + 4}{3}

f (x) = lo g_{4} (x - 3)

f (x) = ln (x + 8)

f (x) = \frac{( 2 x ^{2} - 6 x + 4 )}{( - 3 x - 5 )}

What is the domain of f(x)=(x^2-x)/(sqrt(x^2-1)) ?
The domain of f(x)=(x^2-x)/(sqrt(x^2-1)) is x<-1\lor x>1