What is the domain of f(x)= 1/(sqrt(1.4x-9.3x^2)) ?

The domain of f(x)= 1/(sqrt(1.4x-9.3x^2)) is 0<x< 14/93

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domain of f(x)= 1/(sqrt(1.4x-9.3x^2))

domain

f (x) = \frac{1}{1.4 x - 9.3 x ^{2}}

0 < x < \frac{14}{93}

Interval Notation

(0, \frac{14}{93})

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{14}{93}

Find undefined (singularity) points:

x = 0, x = \frac{14}{93}

Combine real regions and undefined points for final function domain

0 < x < \frac{14}{93}

f (x) = \frac{1}{4 x - 1}

\frac{2 x + 3}{x + 2}

f (x) = \frac{x}{x ^{2} + 3 x}

f (x) = \frac{5 x ^{3} - x ^{2} + 4}{3 x ^{3} + 24}

6 - 3 x

What is the domain of f(x)= 1/(sqrt(1.4x-9.3x^2)) ?
The domain of f(x)= 1/(sqrt(1.4x-9.3x^2)) is 0<x< 14/93