What is the domain of (3x^2)/(x^2-16) ?

The domain of (3x^2)/(x^2-16) is x 4

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domain of (3x^2)/(x^2-16)

domain

\frac{3 x ^{2}}{x ^{2} - 16}

x < - 4 or - 4 < x < 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (- 4, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 4

The function domain

x < - 4 or - 4 < x < 4 or x > 4

f (x) = x x^{2} - 2

f (x) = - lo g_{3} (x)

f (x) = cosh (x)

f (x) = lo g_{3} (x + 5)

What is the domain of (3x^2)/(x^2-16) ?
The domain of (3x^2)/(x^2-16) is x<-4\lor-4<x<4\lor x>4