What is the domain of (x^2+3x-10)/((x+1)(x-3)(x+5)) ?

The domain of (x^2+3x-10)/((x+1)(x-3)(x+5)) is x 3

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domain of (x^2+3x-10)/((x+1)(x-3)(x+5))

domain

\frac{x ^{2} + 3 x - 10}{( x + 1 ) ( x - 3 ) ( x + 5 )}

x < - 5 or - 5 < x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 5) \cup (- 5, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 3, x = - 5

The function domain

x < - 5 or - 5 < x < - 1 or - 1 < x < 3 or x > 3

- 3 + 2 (x + 1)^{4}

f (x) = - \frac{1}{2} x - 3

x^{2} + 4 x + 3

ln (\frac{- 3}{( x + 2 ) ( x - 6 )})

f (x) = \frac{3}{2 + x ^{2}}

What is the domain of (x^2+3x-10)/((x+1)(x-3)(x+5)) ?
The domain of (x^2+3x-10)/((x+1)(x-3)(x+5)) is x<-5\lor-5<x<-1\lor-1<x<3\lor x>3