What is the domain of f(x)=(x+4)/(x^2-2x-3) ?

The domain of f(x)=(x+4)/(x^2-2x-3) is x 3

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domain of f(x)=(x+4)/(x^2-2x-3)

domain

f (x) = \frac{x + 4}{x ^{2} - 2 x - 3}

x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 1

The function domain

x < - 1 or - 1 < x < 3 or x > 3

f (x) = cos (arctan (1 - x^{2}))

f (x) = \frac{1 - x}{2 x - 3}

f (x) = 3 x^{2} - 5 x - 2

f (x) = 2 ∣ x ∣

f (x) = \frac{x - 2 + 2}{x ^{2} - 9}

What is the domain of f(x)=(x+4)/(x^2-2x-3) ?
The domain of f(x)=(x+4)/(x^2-2x-3) is x<-1\lor-1<x<3\lor x>3