What is the domain of x/(x^2+64) ?

The domain of x/(x^2+64) is -infinity <x<infinity

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domain of x/(x^2+64)

domain

\frac{x}{x ^{2} + 64}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

3 ∣ x ∣

f (x) = lo g_{3} (3 - 2 x)

f (x) = \frac{x - 4}{x ^{2} + 8 x + 7}

f (x) = \frac{x ^{2} + 6 x + 5}{x ^{2} - 25}

f (x) = \frac{x + 2}{11 - x}

What is the domain of x/(x^2+64) ?
The domain of x/(x^2+64) is -infinity <x<infinity