What is the domain of (-2(x^2-1))/(x^2-4) ?

The domain of (-2(x^2-1))/(x^2-4) is x 2

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domain of (-2(x^2-1))/(x^2-4)

domain

\frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = lo g_{10} (\frac{x + 3}{x - 2})

f (x) = \frac{x + 5}{7}

f (x) = (x - 3)^{2} + 4

f (x) = \frac{2 x + 1}{x - 2}

f (x) = x^{2} - 8 x + 18

What is the domain of (-2(x^2-1))/(x^2-4) ?
The domain of (-2(x^2-1))/(x^2-4) is x<-2\lor-2<x<2\lor x>2