What is the domain of f(x)= 1/(sqrt(5.7x-8.1x^2)) ?

The domain of f(x)= 1/(sqrt(5.7x-8.1x^2)) is 0<x< 19/27

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domain of f(x)= 1/(sqrt(5.7x-8.1x^2))

domain

f (x) = \frac{1}{5.7 x - 8.1 x ^{2}}

0 < x < \frac{19}{27}

Interval Notation

(0, \frac{19}{27})

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{19}{27}

Find undefined (singularity) points:

x = 0, x = \frac{19}{27}

Combine real regions and undefined points for final function domain

0 < x < \frac{19}{27}

x^{2} - 4 x + 7

g (x) = \frac{5}{x - 4}

lo g_{2} (x + 2)

f (x) = \frac{1}{x + 6} + 17

f (x) = lo g_{2} (x + 5)

What is the domain of f(x)= 1/(sqrt(5.7x-8.1x^2)) ?
The domain of f(x)= 1/(sqrt(5.7x-8.1x^2)) is 0<x< 19/27