What is the domain of f(x)=tan(x),-pi<= x<= pi ?

The domain of f(x)=tan(x),-pi<= x<= pi is -pi<= x<-pi/2 \lor-pi/2 <x< pi/2 \lor pi/2 <x<= pi

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domain of f(x)=tan(x),-pi<= x<= pi

domain

f (x) = tan (x), - π \leq x \leq π

- π \leq x < - \frac{π}{2} or - \frac{π}{2} < x < \frac{π}{2} or \frac{π}{2} < x \leq π

Interval Notation

[- π, - \frac{π}{2}) \cup (- \frac{π}{2}, \frac{π}{2}) \cup (\frac{π}{2}, π]

Solution steps

Set the domain to the given interval

- π \leq x \leq π

Take the denominator(s) of

tan (x)

and compare to zero:

x = \frac{π}{2}, x = - \frac{π}{2}

The function domain

- π \leq x < - \frac{π}{2} or - \frac{π}{2} < x < \frac{π}{2} or \frac{π}{2} < x \leq π

f (x) = x^{2} + 8 x + 7

x^{2} - 4 x + 4

f (x) = x^{2} + 2 x + 3

\frac{1 - 3 x}{x - 1}

f (x) = lo g_{3} (4 x - 5)

What is the domain of f(x)=tan(x),-pi<= x<= pi ?
The domain of f(x)=tan(x),-pi<= x<= pi is -pi<= x<-pi/2 \lor-pi/2 <x< pi/2 \lor pi/2 <x<= pi