What is the domain of y=((x+2))/((x-2))-1/(x+3) ?

The domain of y=((x+2))/((x-2))-1/(x+3) is x 2

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domain of y=((x+2))/((x-2))-1/(x+3)

domain

y = \frac{( x + 2 )}{( x - 2 )} - \frac{1}{x + 3}

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

f (x) = x^{4} - 4 x^{3} + 4 x^{2}

y = cot (x)

\frac{6 x - 54}{x ^{2} - x - 30}

f (x) = 2 x - 5, x < 3

What is the domain of y=((x+2))/((x-2))-1/(x+3) ?
The domain of y=((x+2))/((x-2))-1/(x+3) is x<-3\lor-3<x<2\lor x>2