What is the domain of f(x)=(x+1)/(x^2-x-6) ?

The domain of f(x)=(x+1)/(x^2-x-6) is x 3

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domain of f(x)=(x+1)/(x^2-x-6)

domain

f (x) = \frac{x + 1}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

\frac{x + 9}{x ^{2} - 81}

f (x) = \frac{x ^{2} + 2 x}{x + 1}

2 x^{2} - 6 x + 4 - 3 x - 5

y = \frac{1}{x - 5}

3 x^{\frac{2}{3}} - x^{2}

What is the domain of f(x)=(x+1)/(x^2-x-6) ?
The domain of f(x)=(x+1)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3