What is the domain of f(x)=(sqrt(x+8))/(x-2) ?

The domain of f(x)=(sqrt(x+8))/(x-2) is -8 2

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domain of f(x)=(sqrt(x+8))/(x-2)

domain

f (x) = \frac{x + 8}{x - 2}

- 8 \leq x < 2 or x > 2

Interval Notation

[- 8, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 8 \leq x < 2 or x > 2

\frac{x + 5}{x ^{2} + x - 6}

h (x) = x - 3

\frac{12}{∣ x ∣ - 3}

- 4 x - 12

\frac{x + 5}{x ^{2} - 4}

What is the domain of f(x)=(sqrt(x+8))/(x-2) ?
The domain of f(x)=(sqrt(x+8))/(x-2) is -8<= x<2\lor x>2