What is the domain of f(x)=ln(x^2+2x-3) ?

The domain of f(x)=ln(x^2+2x-3) is x 1

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domain of f(x)=ln(x^2+2x-3)

domain

f (x) = ln (x^{2} + 2 x - 3)

x < - 3 or x > 1

Interval Notation

(- \infty, - 3) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 3 or x > 1

The function domain

x < - 3 or x > 1

f (x) = \frac{x}{coth ( x - 1 )}

f (x) = - 7 - x

4 - 2 x

\frac{x ^{2} - 1}{x ^{2} + 1}

f (x) = - 2 cos (3 x - \frac{π}{2})

What is the domain of f(x)=ln(x^2+2x-3) ?
The domain of f(x)=ln(x^2+2x-3) is x<-3\lor x>1