What is the domain of log_{2}(2x-5)-log_{2}(x+3) ?

The domain of log_{2}(2x-5)-log_{2}(x+3) is x> 5/2

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domain of log_{2}(2x-5)-log_{2}(x+3)

domain

lo g_{2} (2 x - 5) - lo g_{2} (x + 3)

x > \frac{5}{2}

Interval Notation

(\frac{5}{2}, \infty)

Solution steps

Find positive values for logs:

x > \frac{5}{2}

The function domain

x > \frac{5}{2}

f (x, y) = \frac{1}{2} x - \frac{6}{x}

f (x) = 21 - x

f (x) = 1 - x - 1

f (x) = x^{3} - 3 x^{2} + 4

f (x) = 8 x^{2} - 7 x + 9

What is the domain of log_{2}(2x-5)-log_{2}(x+3) ?
The domain of log_{2}(2x-5)-log_{2}(x+3) is x> 5/2