What is the domain of y= 1/(4-x^2) ?

The domain of y= 1/(4-x^2) is x 2

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domain of y= 1/(4-x^2)

domain

y = \frac{1}{4 - x ^{2}}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

(x + 4)^{2}

f (x) = (\frac{1}{2}) x^{2}

f (x, y) = 1 + 4 - y^{2}

f (x) = \frac{2 x ^{2}}{x ^{2} + 2 x - 35}

y = \frac{x}{1 - x}

What is the domain of y= 1/(4-x^2) ?
The domain of y= 1/(4-x^2) is x<-2\lor-2<x<2\lor x>2