What is the domain of f(x)=(x-2)/(x^2-13x+40) ?

The domain of f(x)=(x-2)/(x^2-13x+40) is x 8

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domain of f(x)=(x-2)/(x^2-13x+40)

domain

f (x) = \frac{x - 2}{x ^{2} - 13 x + 40}

x < 5 or 5 < x < 8 or x > 8

Interval Notation

(- \infty, 5) \cup (5, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = 5

The function domain

x < 5 or 5 < x < 8 or x > 8

∣ x - 1 ∣

4 x - 9

\frac{x ^{2} - 36}{8 x + 24}

f (x) = arccos (\frac{1}{x})

2^{x} - 1

What is the domain of f(x)=(x-2)/(x^2-13x+40) ?
The domain of f(x)=(x-2)/(x^2-13x+40) is x<5\lor 5<x<8\lor x>8