What is the domain of f(x)=(2x)/(4x^2+x-3) ?

The domain of f(x)=(2x)/(4x^2+x-3) is x 3/4

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domain of f(x)=(2x)/(4x^2+x-3)

domain

f (x) = \frac{2 x}{4 x ^{2} + x - 3}

x < - 1 or - 1 < x < \frac{3}{4} or x > \frac{3}{4}

Interval Notation

(- \infty, - 1) \cup (- 1, \frac{3}{4}) \cup (\frac{3}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{4}, x = - 1

The function domain

x < - 1 or - 1 < x < \frac{3}{4} or x > \frac{3}{4}

5 x - 4

y = - 2 x + 20

f (x) = \frac{1 + x}{e ^{c o s (x)}}

f (x) = \frac{( x - 4 )}{x ^{2}}

f (x) = cot (\frac{π}{3} + 2 x)

What is the domain of f(x)=(2x)/(4x^2+x-3) ?
The domain of f(x)=(2x)/(4x^2+x-3) is x<-1\lor-1<x< 3/4 \lor x> 3/4