What is the domain of f(x)=sqrt(x^2+7) ?

The domain of f(x)=sqrt(x^2+7) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+7)

domain

f (x) = x^{2} + 7

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

- x + 1

\frac{x + 2}{5}

f (x) = \frac{x - 2}{x ^{2} - 2 x - 35}

f (x) = \frac{x - 2}{x + 3}

\frac{1}{x - 2}

What is the domain of f(x)=sqrt(x^2+7) ?
The domain of f(x)=sqrt(x^2+7) is -infinity <x<infinity