What is the domain of f(x)=(sqrt(x-2))/(x+3) ?

The domain of f(x)=(sqrt(x-2))/(x+3) is x>= 2

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domain of f(x)=(sqrt(x-2))/(x+3)

domain

f (x) = \frac{x - 2}{x + 3}

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x \geq 2

\frac{1}{x - 2}

f (x) = \frac{x ( x + 7 )}{x ^{2} + 5 x + 6}

f (x) = 5 + (ln (x^{2} - 4))^{2}

f (x) = \frac{2}{x - 1}

f (x) = \frac{2}{3} x + 3

What is the domain of f(x)=(sqrt(x-2))/(x+3) ?
The domain of f(x)=(sqrt(x-2))/(x+3) is x>= 2