What is the domain of f(x)=(sqrt(2x-3))/(x^2-5x+4) ?

The domain of f(x)=(sqrt(2x-3))/(x^2-5x+4) is 3/2 4

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domain of f(x)=(sqrt(2x-3))/(x^2-5x+4)

domain

f (x) = \frac{2 x - 3}{x ^{2} - 5 x + 4}

\frac{3}{2} \leq x < 4 or x > 4

Interval Notation

[\frac{3}{2}, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{2}

Find undefined (singularity) points:

x = 4, x = 1

Combine real regions and undefined points for final function domain

\frac{3}{2} \leq x < 4 or x > 4

f (x) = sec (x) csc (x)

+ \frac{x + 4}{x - 4}

ln (arccos (x))

f (x) = x^{2} - 2 x + 4

7 x - 21 + \frac{x}{x - 8}

What is the domain of f(x)=(sqrt(2x-3))/(x^2-5x+4) ?
The domain of f(x)=(sqrt(2x-3))/(x^2-5x+4) is 3/2 <= x<4\lor x>4