What is the domain of f(x)=sqrt((x+1)/(x-3)) ?

The domain of f(x)=sqrt((x+1)/(x-3)) is x 3

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domain of f(x)=sqrt((x+1)/(x-3))

domain

f (x) = \frac{x + 1}{x - 3}

x \leq - 1 or x > 3

Interval Notation

(- \infty, - 1] \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x > 3

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \leq - 1 or x > 3

f (x) = ln (\frac{2 + x}{2 - x})

f (x) = 2 x^{2} - 50

f (x) = - \frac{1 - 3 x}{x - 1}

f (x) = \frac{( x - 2 )}{x ^{2} - 16}

f (x) = ln (- 2 x^{2} - 2 x + 40)

What is the domain of f(x)=sqrt((x+1)/(x-3)) ?
The domain of f(x)=sqrt((x+1)/(x-3)) is x<=-1\lor x>3