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Popular >

range of f(x)=(x+2)^2

Solution

range

f (x) = (x + 2)^{2}

Solution

f (x) \geq 0

+1

Interval Notation

[0, \infty)

Solution steps

Vertex of

(x + 2)^{2} :

Minimum

(- 2, 0)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 2, 0)

f (x) \geq 0

Popular Examples

inverse of f(x)=(x+3)^2+1 inverse

f (x) = (x + 3)^{2} + 1

domain of f(x)=(7x)/(x^2+x-2)domain

f (x) = \frac{7 x}{x ^{2} + x - 2}

inflection x^3-3x^2-9x+10 inflection points

x^{3} - 3 x^{2} - 9 x + 10

distance (1,-19),(8,-14)distance

(1, - 19), (8, - 14)

x = 8

Frequently Asked Questions (FAQ)

What is the range of f(x)=(x+2)^2 ?
The range of f(x)=(x+2)^2 is f(x)>= 0