What is the domain of f(x)=(2x^2-6x+4)/(3x-5) ?

The domain of f(x)=(2x^2-6x+4)/(3x-5) is x 5/3

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domain of f(x)=(2x^2-6x+4)/(3x-5)

domain

f (x) = \frac{2 x ^{2} - 6 x + 4}{3 x - 5}

x < \frac{5}{3} or x > \frac{5}{3}

Interval Notation

(- \infty, \frac{5}{3}) \cup (\frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{3}

The function domain

x < \frac{5}{3} or x > \frac{5}{3}

f (x) = \frac{4 - 3 x}{x + 5}

f (x) = \frac{x - 4}{x ^{2} + 5 x - 36}

f (x) = 16 x - 25

g (x) = \frac{x}{4 x ^{2} - 9}

f (x) = \frac{6 x}{x ^{2} - 2 x}

What is the domain of f(x)=(2x^2-6x+4)/(3x-5) ?
The domain of f(x)=(2x^2-6x+4)/(3x-5) is x< 5/3 \lor x> 5/3