What is the domain of f(x)=2tan(2x)+1 ?

The domain of f(x)=2tan(2x)+1 is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=2tan(2x)+1

domain

f (x) = 2 tan (2 x) + 1

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

Interval Notation

[\frac{π}{2} n, \frac{π}{4} + \frac{π}{2} n) \cup (\frac{π}{4} + \frac{π}{2} n, \frac{π}{2} + \frac{π}{2} n)

Solution steps

Take the denominator(s) of

2 tan (2 x) + 1

and compare to zero:

x = \frac{π}{4} + \frac{π}{2} n

Periodicity of

2 tan (2 x) + 1 : \frac{π}{2}

Combine period:

\frac{π}{2} n \leq x < \frac{π}{2} + \frac{π}{2} n

and undefined points.

The domain is

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

f (x) = - x^{3} + 3 x^{2}

f (x) = \frac{x - a}{x + π}

f (x) = \frac{4}{5} x

\frac{1}{3 - x}

\frac{x - 6}{x + 2}

What is the domain of f(x)=2tan(2x)+1 ?
The domain of f(x)=2tan(2x)+1 is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n