What is the domain of g(x)=sqrt(1-x^2) ?

The domain of g(x)=sqrt(1-x^2) is -1<= x<= 1

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domain of g(x)=sqrt(1-x^2)

domain

g (x) = 1 - x^{2}

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

(x^{3} - 1)^{\frac{2}{3}}

3 x + \frac{6}{5}

- x + 4 - 2

f (x) = \frac{1}{x - 8}

\frac{1}{x ^{2} - 3 x - 4}

What is the domain of g(x)=sqrt(1-x^2) ?
The domain of g(x)=sqrt(1-x^2) is -1<= x<= 1