What is the domain of f(x)=sqrt(2x+2) ?

The domain of f(x)=sqrt(2x+2) is x>=-1

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domain of f(x)=sqrt(2x+2)

domain

f (x) = 2 x + 2

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = \frac{2 x - 5}{x - 3}

y = 2 x - 3

f (x) = \frac{x ^{2} - 2}{( x + 2 ) ^{2}}

- \frac{13}{( 4 + x ) ^{2}}

\frac{7 x}{8 x - 1}