What is the domain of f(x)=sqrt(x+1)-4 ?

The domain of f(x)=sqrt(x+1)-4 is x>=-1

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domain of f(x)=sqrt(x+1)-4

domain

f (x) = x + 1 - 4

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = \frac{x + 2}{x - 5}

f (x) = lo g_{10} (x + 5)

f (x) = \frac{3}{cos ( x ) + 1}

3 x - 5

f (x) = x^{2} - 3 x + 4

What is the domain of f(x)=sqrt(x+1)-4 ?
The domain of f(x)=sqrt(x+1)-4 is x>=-1