What is the domain of f(x)=sqrt(4-x^2)+sqrt(x^2-4) ?

The domain of f(x)=sqrt(4-x^2)+sqrt(x^2-4) is x=-2\lor x=2

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domain of f(x)=sqrt(4-x^2)+sqrt(x^2-4)

domain

f (x) = 4 - x^{2} + x^{2} - 4

x = - 2 or x = 2

Interval Notation

x = - 2 \cup x = 2

Solution steps

Find non-negative values for radicals:

x = - 2 or x = 2

The function domain

x = - 2 or x = 2

\frac{x + 5}{2}

f (x) = - 2 x^{2} + 6 x

f (x) = x^{2} - 5 x + 4

y = (x - 1)^{2}

f (x) = \frac{1}{\frac{x}{x + 1}}

What is the domain of f(x)=sqrt(4-x^2)+sqrt(x^2-4) ?
The domain of f(x)=sqrt(4-x^2)+sqrt(x^2-4) is x=-2\lor x=2