What is the domain of f(x)=(x+1)/(x^2+1) ?

The domain of f(x)=(x+1)/(x^2+1) is -infinity <x<infinity

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domain of f(x)=(x+1)/(x^2+1)

domain

f (x) = \frac{x + 1}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x + 6}{2 x - 5}

y = \frac{2 x + 5}{3 - x}

f (x) = 2^{- x + 1} + 3

f (x) = \frac{2}{x 3 ^{\frac{1}{3}}}

f (x) = \frac{x + 3}{x - 1}

What is the domain of f(x)=(x+1)/(x^2+1) ?
The domain of f(x)=(x+1)/(x^2+1) is -infinity <x<infinity