What is the domain of f(x)= x/(sqrt(x^2+1)) ?

The domain of f(x)= x/(sqrt(x^2+1)) is -infinity <x<infinity

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domain of f(x)= x/(sqrt(x^2+1))

domain

f (x) = \frac{x}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x^{2} + 4 x - 5

f (x) = 2 x^{2} - 6

f (x) = \frac{( x + 1 )}{x + 4}

f (x) = ln (5 - x^{2})

f (x) = e^{x + 2}

What is the domain of f(x)= x/(sqrt(x^2+1)) ?
The domain of f(x)= x/(sqrt(x^2+1)) is -infinity <x<infinity