What is the domain of (2x^2)/(x^2-25) ?

The domain of (2x^2)/(x^2-25) is x 5

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domain of (2x^2)/(x^2-25)

domain

\frac{2 x ^{2}}{x ^{2} - 25}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = \frac{17 x - 30}{33 x - 29}

- 3 x + 8

f (x) = ln (\frac{1 + x}{1 - x})

f (x) = 3 x^{2} - 5 x - 6

- 3^{x}

What is the domain of (2x^2)/(x^2-25) ?
The domain of (2x^2)/(x^2-25) is x<-5\lor-5<x<5\lor x>5