What is the inverse of f(x)=-sqrt(1-x^2) ?

The inverse of f(x)=-sqrt(1-x^2) is sqrt(-x^2+1),-sqrt(-x^2+1)

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inverse of f(x)=-sqrt(1-x^2)

inverse

f (x) = - 1 - x^{2}

- x^{2} + 1, - - x^{2} + 1

Solution steps

y = - 1 - x^{2}

Replace

x

with

y

x = - 1 - y^{2}

Solve for

y, x = - 1 - y^{2}

- x^{2} + 1, - - x^{2} + 1

f (x) = 2 (x + 3)^{3}

y = 3 sin (π x + 2) - 3

f (x) = x^{5} - 4 x^{3} + 2 x

arccos (2 y)

f (x) = \frac{( x ^{2} - 25 )}{x ^{2} - 4 x - 5}

What is the inverse of f(x)=-sqrt(1-x^2) ?
The inverse of f(x)=-sqrt(1-x^2) is sqrt(-x^2+1),-sqrt(-x^2+1)