What is the domain of f(x)=((2x-3))/(5x-7) ?

The domain of f(x)=((2x-3))/(5x-7) is x 7/5

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domain of f(x)=((2x-3))/(5x-7)

domain

f (x) = \frac{( 2 x - 3 )}{5 x - 7}

x < \frac{7}{5} or x > \frac{7}{5}

Interval Notation

(- \infty, \frac{7}{5}) \cup (\frac{7}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{7}{5}

The function domain

x < \frac{7}{5} or x > \frac{7}{5}

f (x) = ln (2 x - 1)

y = 0

f (x) = ln (3 - x - 1)

f (x) = x^{\frac{4}{3}} - 2 x^{\frac{1}{3}}

f (x) = - x^{2} + 6 x - 4

What is the domain of f(x)=((2x-3))/(5x-7) ?
The domain of f(x)=((2x-3))/(5x-7) is x< 7/5 \lor x> 7/5