What is the domain of f(x)=(sqrt(x+1))/(x-2) ?

The domain of f(x)=(sqrt(x+1))/(x-2) is -1 2

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domain of f(x)=(sqrt(x+1))/(x-2)

domain

f (x) = \frac{x + 1}{x - 2}

- 1 \leq x < 2 or x > 2

Interval Notation

[- 1, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 1 \leq x < 2 or x > 2

f (x) = \frac{1}{( 3 x ^{2} + 17 x - 6 )}

f (x) = ∣ x ∣ + 1

f (x) = x - 2 - 1

f (x) = \frac{x ^{3} + 2 x ^{2}}{3 x ^{2} - 1}

f (x) = arcsin (ln (x))

What is the domain of f(x)=(sqrt(x+1))/(x-2) ?
The domain of f(x)=(sqrt(x+1))/(x-2) is -1<= x<2\lor x>2