What is the domain of sqrt(4+5/(x^2-1)) ?

The domain of sqrt(4+5/(x^2-1)) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(4+5/(x^2-1))

domain

4 + \frac{5}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x > 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = 7 x + 9

f (x) = - x^{2} + 2

f (x) = sin (4 x)

f (x) = \frac{2 x ^{2} - 8}{x ^{2} + x - 2}

f (x) = \frac{1}{2 x + 1} - \frac{3}{2 - 3 x}

What is the domain of sqrt(4+5/(x^2-1)) ?
The domain of sqrt(4+5/(x^2-1)) is x<-1\lor x>1