What is the domain of f(x)=(x+1)/(x^3-4x) ?

The domain of f(x)=(x+1)/(x^3-4x) is x 2

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domain of f(x)=(x+1)/(x^3-4x)

domain

f (x) = \frac{x + 1}{x ^{3} - 4 x}

x < - 2 or - 2 < x < 0 or 0 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2, x = 2

The function domain

x < - 2 or - 2 < x < 0 or 0 < x < 2 or x > 2

f (x) = \frac{9}{x ^{2} - 7 x}

\frac{x - 1}{x - 4}

f (x) = 25 - x^{2}

f (x) = \frac{( e ^{x} )}{1 - e ^{x}}

x - \frac{1}{x}

What is the domain of f(x)=(x+1)/(x^3-4x) ?
The domain of f(x)=(x+1)/(x^3-4x) is x<-2\lor-2<x<0\lor 0<x<2\lor x>2