What is the domain of f(x)=(2x+4)/(x^2+3x-40) ?

The domain of f(x)=(2x+4)/(x^2+3x-40) is x 5

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domain of f(x)=(2x+4)/(x^2+3x-40)

domain

f (x) = \frac{2 x + 4}{x ^{2} + 3 x - 40}

x < - 8 or - 8 < x < 5 or x > 5

Interval Notation

(- \infty, - 8) \cup (- 8, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 8

The function domain

x < - 8 or - 8 < x < 5 or x > 5

f (x) = \frac{2 x - 7}{3 x + 5}

f (x) = \frac{2 x}{9 x - 1}

y = 2 x - 4

f (x) = x^{2} - 10 x + 21

f (x) = \frac{7 x}{8 x - 3}

What is the domain of f(x)=(2x+4)/(x^2+3x-40) ?
The domain of f(x)=(2x+4)/(x^2+3x-40) is x<-8\lor-8<x<5\lor x>5